是否可以从节点js中的同一模块导出构造函数和一些正常函数？

My app structure:

我的app结构:

| my-application
| -- app.js
| -- node_modules
| -- public
| -- models
     | -- users.js
| -- routes
     | -- index.js
| -- views
     | -- index.ejs

users.js

function User(name){
   this.name = name;
}

User.prototype.getName = function () {
   return this.name;
};

exports.checkName = function (name) {
   if(name === 'johnSnow'){
      return true;
   }
   return false;
};

module.exports = User;

And i try this:

我试试这个:

index.js

var user  = require('../models/users');

if( user.checkName('dinar') === true ){
    var User = new user('name');
    console.log(User.getName());
}

TypeError: user.checkName is not a function

TypeError:user.checkName不是函数

Is it possible to use functions and constructor function from same module?

是否可以使用同一模块中的函数和构造函数?

Is there any way to do this?

有没有办法做到这一点?

I'm new in node js.

我是节点js的新手。

Thanks in Advance.

提前致谢。

3 个解决方案

#1

Yes, it's possible, by putting the normal function as a "static" method on the constructor function itself. In your attempt, you were overwriting the exports object with User so the checkName was lost. Instead, do

是的,通过将普通函数作为“静态”方法放在构造函数本身上是可能的。在您的尝试中,您使用User覆盖了导出对象,因此checkName丢失了。相反,做

function User(name){
   this.name = name;
}

User.prototype.getName = function () {
   return this.name;
};

User.checkName = function (name) { /*
^^^^ */
   return name === 'johnSnow';
};

module.exports = User;

Or alternatively you might want to write

或者你可能想写

module.exports = User;
module.exports.checkName = function (name) {
   return name === 'johnSnow';
};

3 个解决方案

#1

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