美元。针对简单的php, post返回对象

I guess I'm just having difficulty with $.post... I've used it successfully in the past, but I have to be forgetting something important. All I want is a "hello world", but I'm getting a complicated object. I am befuddled.

我想我只是对$.post有困难。我曾经成功地使用过它，但我不得不忘记一些重要的东西。我只想要一个“你好世界”，但我得到了一个复杂的对象。我糊里糊涂的。

var_test.php

var_test.php

<?php
    PRINT "hi";
?>

index.html

index . html

<!doctype html>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<html><head>
    var thing = $.post( "var_test.php");
    console.log(thing);
</head><body></body></html>

console output

控制台输出

Object { readyState: 1, getResponseHeader: .ajax/v.getResponseHeader(), getAllResponseHeaders: .ajax/v.getAllResponseHeaders(), setRequestHeader: .ajax/v.setRequestHeader(), overrideMimeType: .ajax/v.overrideMimeType(), statusCode: .ajax/v.statusCode(), abort: .ajax/v.abort(), state: .Deferred/d.state(), always: .Deferred/d.always(), then: .Deferred/d.then(), 8 more… }

3 个解决方案

#1

You should add a callback instead that receives the response/data from your php:

您应该添加一个回调函数来接收来自php的响应/数据:

$.post( "var_test.php", function(response) {
    console.log(response);
});

That callback will be executed once the request has finished, that way, you can be sure that you will have your data ready and set to use it in your JS.

该回调将在请求完成后执行，这样，您就可以确保准备好数据并将其设置为在JS中使用。

3 个解决方案

#1

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