XSL：包括根本不工作

Here is my setup:

这是我的设置:

<?xml version="1.0"?>
<xsl:transform  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:include href="top.xsl"/>  
<xsl:template match="">
Content here - divs and such
</xsl:template>            
</xsl:transform>

Then this is the stylesheet that I am trying to include.

然后这是我想要包含的样式表。

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
<xsl:template match="/">
Standard html file now, html, head,title,script,body etc.

Closes like this:

这样关闭:

<xsl:apply-templates />
        </body>
    </html>
</xsl:template>

</xsl:stylesheet>

Why won't the include work?

为什么包含不起作用?

Edit: Here is the full code: https://gist.github.com/anonymous/3432742335a8fd3c600f

编辑:这是完整的代码:https://gist.github.com/anonymous/3432742335a8fd3c600f

1 个解决方案

#1

When you do <xsl:apply-templates /> in your nav.xsl this will look for child nodes of the document node. As XML needs a single root element to be well-formed, you can replace your currently empty template match with this to match this root element

在nav.xsl中执行时,将查找文档节点的子节点。由于XML需要单个根元素格式良好,因此可以使用此替换当前为空的模板匹配以匹配此根元素

<xsl:template match="/*" >

1 个解决方案

#1

更多相关文章

随机推荐