为$ .plugin（）用法准备插件而不是$（selector）.plugin（）

Simply:

(function($){
    $.fn.plugin = function()
    {
        // results in error
        // when called like
        // $.plugin();
    }
})(jQuery);

The error is (copied from Chrome console):

错误是(从Chrome控制台复制):

Uncaught TypeError: Object function ( selector, context ) {
        // The jQuery object is actually just the init constructor 'enhanced'
        return new jQuery.fn.init( selector, context, rootjQuery );
    } has no method 'plugin'

What rules I have to follow in order to make my plugin work without the element selection?

我必须遵循哪些规则才能使我的插件在没有元素选择的情况下工作?

3 个解决方案

#1

Simply assign the function directly to $.plugin:

只需将函数直接分配给$ .plugin:

(function($){
    $.plugin = function()
    {
        // ...
    }
})(jQuery);

Of course this won't refer to selected elements anymore, but to jQuery itself.

当然,这不会再引用所选元素,而是引用jQuery本身。

3 个解决方案

#1

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