python 按位置关系输出矩阵元素

描述：依次输出矩阵中最近邻的元素

例如：输入:

[[1, 2, 3]

[4, 5, 6]

[7, 8, 9]]

输出：

[[ 1. 2. 4. 5. 3. 6. 7. 8. 9.]
[ 2. 1. 3. 4. 5. 6. 7. 8. 9.]
[ 3. 2. 5. 6. 1. 4. 7. 8. 9.]
[ 4. 1. 2. 5. 7. 8. 3. 6. 9.]
[ 5. 1. 2. 3. 4. 6. 7. 8. 9.]

思想：采用坐标进行判断，距离中心点一跳的元素坐标与中心点的坐标的平方差小于2，依次类推

import numpy as np
#zhaodaozaizhidingfanweineideshuzi
a=np.array([[1,2,3],[4,5,6],[7,8,9]])
b=a[0][0]
c,d=a.shape
e=np.zeros(shape=[c*d,c*d])
# print (d)
k=0

def sround1(distance,m,n,wend,hend):
    e[m*3+n][0]=a[m][n]
    k=1
    for d in range(distance):
        for i in range(wend):
            for j in range(hend):
                if np.square(i-m)+np.square(j-n)<=2*np.square(d) and np.square(i-m)+np.square(j-n)>2*np.square(d-1):
                    e[m*3+n][k]=a[i][j]
                    k=k+1
                    print (e)


def start(c, d):
    d=max(c,d)
    for i in range(c):
        for j in range(d):
            sround1(d,i,j,c,d)
    print (e)

if __name__=='__main__':
    start(3,3)

更多相关文章

随机推荐