分离RegEx模式匹配具有相同的潜在启动字符。

I would like to have a RegEx that matches several of the same character in a row, within a range of possible characters but does not return those pattern matches as one pattern. How can this be accomplished?

我希望有一个RegEx，它可以匹配行中的几个相同字符，在可能的字符范围内，但不返回这些模式匹配为一个模式。这是如何实现的呢?

For clarification:

澄清:

I want a pattern that starts with [a-c] and ungreedly returns any number of the same character, but not the other characters in the range. In the sequence 'aafaabbybcccc' it would find patterns for:

我想要一个以[a-c]开头的模式，并且不带灰色地返回任何数量的相同字符，但不返回范围中的其他字符。在“aafaabbybcccc”序列中，它会找到以下模式:

('aa', 'aa', 'bb', 'b', 'cccc')

(“aa”、“aa”、“bb”、“b”、“cccc”)

but would exclude the following:

但将排除下列因素:

('f', 'aabb', 'y', 'bcccc')

(' f ',' aabb ',' y ','主教团')

I don't want to use multiple RegEx pattern searches because the order that i find the patterns will determine the output of another function. This question is for the purposes of self study (python), not homework. (I'm also under 15 rep but will come back and upvote when I can.)

我不想使用多个RegEx模式搜索，因为我找到模式的顺序将决定另一个函数的输出。这个问题是为了自学(python)，而不是家庭作业。(我也在15岁以下，但如果可以的话，我会回来投票。)

2 个解决方案

#1

Good question. Use a regex like:

好问题。使用一个正则表达式:

(?P<L>[a-c])(?P=L)+

This is more robust - you're not limited to a-c, you can replace it with a-z if you like. It first defines any character within a-c as L, then sees whether that character occurs again one or more times. You want to run re.findall() using this regex.

这更健壮——你不局限于a-c，你可以用a-z替换它。它首先将a-c中的任何字符定义为L，然后查看该字符是否再次出现一次或多次。您希望使用此regex运行re.findall()。

2 个解决方案

#1

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