Bash脚本删除目录中多个文件名末尾的'x'字符数量？

I have a list of file names in a directory (/path/to/local). I would like to remove a certain number of characters from all of those filenames.

我在目录中有一个文件名列表(/ path / to / local)。我想从所有这些文件名中删除一定数量的字符。

Example filenames:

iso1111_plane001_00321.moc1
iso1111_plane002_00321.moc1
iso2222_plane001_00123.moc1

In every filename I wish to remove the last 5 characters before the file extension.

在每个文件名中,我希望删除文件扩展名之前的最后5个字符。

For example:

iso1111_plane001_.moc1
iso1111_plane002_.moc1
iso2222_plane001_.moc1

I believe this can be done using sed, but I cannot determine the exact coding. Something like...

我相信这可以使用sed完成,但我无法确定确切的编码。就像是...

for filename in /path/to/local/*.moc1; do
    mv $filname $(echo $filename | sed -e 's/.....^//');
done

...but that does not work. Sorry if I butchered the sed options, I do not have much experience with it.

......但那不起作用。对不起,如果我屠杀了sed选项,我没有太多的经验。

3 个解决方案

 mv $filname $(echo $filename | sed -e 's/.....\.moc1$//');

 echo ${filename%%?????.moc1}.moc1

%% is a bash internal operator...

%%是一个bash内部运算符......