导致org.hibernate创建记录。MappingException:未知的实体

I am trying to create a record in a table but it gives me the following exception.

我试图在一个表中创建一个记录，但是它给了我下面的异常。

org.hibernate.MappingException: Unknown entity: com.Person

My get(Person person) method works fine and returns the result.

我的get(Person)方法可以正常工作并返回结果。

DAO class:

DAO类:

public void create(Person person){
    Session session = HibernateUtil.getSession();
    Transaction tx = session.beginTransaction();

    session.save(person);//----------------------->this throws exception
    session.flush();
    tx.commit();
    session.close();
}

public List<Person> get(Person person){
    criteria = createCriteria("person");
    criteria.add(Restrictions.eq("person", person.getFirstName()));
    return criteria.list();     
}

hibernate.cfg.xml file:

hibernate.cfg。xml文件:

<hibernate-configuration>
    <session-factory>
        //other database properties
        <mapping resource="com/Person.hbm.xml" />
    </session-factory>
</hibernate-configuration>

Person.hbm.xml file:

Person.hbm。xml文件:

<hibernate-mapping default-lazy="false">
    <class name="com.Person" table="Person" entity-name="person">
        <id name="personId" type="integer" column="PERSON_ID">
            <generator class="increment"/>
        </id>
        <property name="firstName" column="FIRST_NAME"/>
        <property name="address" column="ADDRESS"/>
    </class>   
</hibernate-mapping>

Entity mapped to table Person:

映射到table Person的实体:

public class Person implements Serializable{
    private Integer personId;
    private String firstName;
    private String address;

    public Person(){}

    //getters setters
}

1 个解决方案

#1

The issue is caused by using the entity-name property in your hbm.xml file. If you do this then you must also provide the same entity-name when you call save:

这个问题是由在hbm中使用实体名称属性引起的。xml文件。如果这样做，那么在调用save时也必须提供相同的实体名称:

session.save("person", person);

A cleaner option would be to remove the entity-name property from your mapping file so you can just call save(person) w/o having to provide an entity-name (it defaults to the FQ class name). Then create your criteria by passing the class instead of a string name. For example:

一个更干净的选项是，从映射文件中删除实体名称属性，这样您就可以调用save(person) w/o，它必须提供一个实体名称(它默认为FQ类名称)。然后通过传递类而不是字符串名称来创建标准。例如:

session.createCriteria(Person.class);

1 个解决方案

#1

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