Android(安卓)点击两次返回键退出程序

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<spanstyle="font-size:14px;">packagecom.test.twiceexit;
importjava.util.Timer;
importandroid.app.Activity;
importandroid.os.Bundle;
importandroid.os.Handler;
importandroid.os.Message;
importandroid.view.KeyEvent;
importandroid.view.Menu;
importandroid.widget.Toast;
publicclassMainActivityextendsActivity{
privatestaticBooleanisQuit=false;
privatelongmExitTime=0;
Timertimer=newTimer();
@Override
protectedvoidonCreate(BundlesavedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
publicbooleanonCreateOptionsMenu(Menumenu){
//Inflatethemenu;thisaddsitemstotheactionbarifitispresent.
getMenuInflater().inflate(R.menu.main,menu);
returntrue;
}
/**************************************************
*方法一
*************************************************/
//@Override
//publicbooleanonKeyDown(intkeyCode,KeyEventevent){
//if(keyCode==KeyEvent.KEYCODE_BACK){
//if(isQuit==false){
//isQuit=true;
//Toast.makeText(getBaseContext(),"再按一次返回键退出程序",
//Toast.LENGTH_SHORT).show();
//TimerTasktask=null;
//task=newTimerTask(){
//publicvoidrun(){
//isQuit=false;
//}
//};
//timer.schedule(task,2000);
//}else{
//finish();
//System.exit(0);
//}
//}
//returnfalse;
//}
/**************************************************
*方法二
*************************************************/
//@Override
//publicbooleanonKeyDown(intkeyCode,KeyEventevent){
//if(keyCode==KeyEvent.KEYCODE_BACK){
//if((System.currentTimeMillis()-mExitTime)>2000){//
////如果两次按键时间间隔大于2000毫秒，则不退出
//Toast.makeText(this,"再按一次退出程序",Toast.LENGTH_SHORT).show();
//mExitTime=System.currentTimeMillis();//更新mExitTime
//}else{
//System.exit(0);//否则退出程序
//}
//returntrue;
//}
//returnsuper.onKeyDown(keyCode,event);
//
//}
/**************************************************
*方法三
*************************************************/
HandlermHandler=newHandler(){
@Override
publicvoidhandleMessage(Messagemsg){
super.handleMessage(msg);
isQuit=false;
}
};
@Override
publicbooleanonKeyDown(intkeyCode,KeyEventevent){
if(keyCode==KeyEvent.KEYCODE_BACK){
if(!isQuit){
isQuit=true;
Toast.makeText(getApplicationContext(),"再按一次退出程序",
Toast.LENGTH_SHORT).show();
//利用handler延迟发送更改状态信息
mHandler.sendEmptyMessageDelayed(0,2000);
}else{
finish();
System.exit(0);
}
}
returnfalse;
}
}
</span>

推荐使用第二种，该方法相对来说降低系统消耗！

源码地址：http://download.csdn.net/detail/dadaxiaoxiaode/5815849

ref:http://blog.csdn.net/yelangjueqi/article/details/9472705

http://blog.csdn.net/h7870181/article/details/8906596

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