Android通过PopupMenu定义弹出菜单的位置

效果如图：

具体实现代码如下：

package com.example.mytest;import android.app.Activity;import android.os.Bundle;import android.support.v4.app.FragmentActivity;import android.view.Menu;import android.view.MenuItem;import android.view.View;import android.view.View.OnClickListener;import android.widget.Button;import android.widget.PopupMenu;import android.widget.Toast;public class MainActivity extends Activity {@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setContentView(R.layout.activity_main);Button btn = (Button) findViewById(R.id.btn);btn.setOnClickListener(new OnClickListener() {@Overridepublic void onClick(View v) {showPopupMenu(v);}});}private void showPopupMenu(View view) {// View当前PopupMenu显示的相对View的位置PopupMenu popupMenu = new PopupMenu(this, view);// menu布局popupMenu.getMenuInflater().inflate(R.menu.main, popupMenu.getMenu());// menu的item点击事件popupMenu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {@Overridepublic boolean onMenuItemClick(MenuItem item) {Toast.makeText(getApplicationContext(), item.getTitle(), Toast.LENGTH_SHORT).show();return false;}});// PopupMenu关闭事件popupMenu.setOnDismissListener(new PopupMenu.OnDismissListener() {@Overridepublic void onDismiss(PopupMenu menu) {Toast.makeText(getApplicationContext(), "关闭PopupMenu", Toast.LENGTH_SHORT).show();}});popupMenu.show();}}

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