Android处理大图片

项目中经常碰到需要处理大图片的问题，因为android对应用分配资源的限制，如果不进行相应的处理，容易造成OOM。

Android处理大图的方法：

对于大图先获取出图片的width和height, 然后根据view的width和height, 换算出图片inSampleSize,，最后压缩生成相应的图片。

其中重要的两个参数是：

/**111         * If set to true, the decoder will return null (no bitmap), but112         * the out... fields will still be set, allowing the caller to query113         * the bitmap without having to allocate the memory for its pixels.114         */115        public boolean inJustDecodeBounds;116117        /**118         * If set to a value > 1, requests the decoder to subsample the original119         * image, returning a smaller image to save memory. The sample size is120         * the number of pixels in either dimension that correspond to a single121         * pixel in the decoded bitmap. For example, inSampleSize == 4 returns122         * an image that is 1/4 the width/height of the original, and 1/16 the123         * number of pixels. Any value <= 1 is treated the same as 1. Note: the124         * decoder uses a final value based on powers of 2, any other value will125         * be rounded down to the nearest power of 2.126         */127        public int inSampleSize;

InJustDecodeBounds能在不分配资源给图片的情况下获取图片的大小

inSampleSize计算图片的压缩比

开源项目xutils, Universal-Image-Loader和Foursquare对于大图的处理都类似的

下面是Foursquare处理大图的代码：

public class ImageUtils {        private ImageUtils() {    }    public static void resampleImageAndSaveToNewLocation(String pathInput, String pathOutput)         throws Exception     {        Bitmap bmp = resampleImage(pathInput, 640);                OutputStream out = new FileOutputStream(pathOutput);        bmp.compress(Bitmap.CompressFormat.JPEG, 90, out);     }        public static Bitmap resampleImage(String path, int maxDim)         throws Exception {                BitmapFactory.Options bfo = new BitmapFactory.Options();         bfo.inJustDecodeBounds = true;         BitmapFactory.decodeFile(path, bfo);             BitmapFactory.Options optsDownSample = new BitmapFactory.Options();        optsDownSample.inSampleSize = getClosestResampleSize(bfo.outWidth, bfo.outHeight, maxDim);            Bitmap bmpt = BitmapFactory.decodeFile(path, optsDownSample);            Matrix m = new Matrix();                 if (bmpt.getWidth() > maxDim || bmpt.getHeight() > maxDim) {            BitmapFactory.Options optsScale = getResampling(bmpt.getWidth(), bmpt.getHeight(), maxDim);            m.postScale((float)optsScale.outWidth  / (float)bmpt.getWidth(),                         (float)optsScale.outHeight / (float)bmpt.getHeight());         }                 int sdk = new Integer(Build.VERSION.SDK).intValue();         if (sdk > 4) {            int rotation = ExifUtils.getExifRotation(path);            if (rotation != 0) {                 m.postRotate(rotation);             }        }                return Bitmap.createBitmap(bmpt, 0, 0, bmpt.getWidth(), bmpt.getHeight(), m, true);     }        private static BitmapFactory.Options getResampling(int cx, int cy, int max) {        float scaleVal = 1.0f;        BitmapFactory.Options bfo = new BitmapFactory.Options();        if (cx > cy) {            scaleVal = (float)max / (float)cx;        }        else if (cy > cx) {            scaleVal = (float)max / (float)cy;        }        else {            scaleVal = (float)max / (float)cx;        }        bfo.outWidth  = (int)(cx * scaleVal + 0.5f);        bfo.outHeight = (int)(cy * scaleVal + 0.5f);        return bfo;    }        private static int getClosestResampleSize(int cx, int cy, int maxDim) {        int max = Math.max(cx, cy);                int resample = 1;        for (resample = 1; resample < Integer.MAX_VALUE; resample++) {            if (resample * maxDim > max) {                resample--;                break;            }        }                if (resample > 0) {            return resample;        }        return 1;    }        public static BitmapFactory.Options getBitmapDims(String path) throws Exception {        BitmapFactory.Options bfo = new BitmapFactory.Options();         bfo.inJustDecodeBounds = true;         BitmapFactory.decodeFile(path, bfo);         return bfo;    }}

还有一个问题需要纠正:
看了几篇关于处理大图的文章都说不要调用BitmapFactory.decodeResource这个函数，因为这个函数在完成decode后，最终都是通过java层的createBitmap来完成的，需要消耗更多内存。
我看了BitmapFactory的源码发现上面那个分析是错误的，decodeResource最终也是调用Jni去获取图片。请看下面时序图。

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