android startService小例子
16lz
2021-12-04
MainActivity.java类
package com.example.xservice; import android.os.Bundle; import android.app.Activity; import android.content.Intent; import android.view.Menu; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; public class MainActivity extends Activity { private Button btn1,btn2; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); btn1=(Button)findViewById(R.id.btn1); btn2=(Button)findViewById(R.id.btn2); btn1.setOnClickListener(listener); btn2.setOnClickListener(listener); } private OnClickListener listener=new OnClickListener() { @Override public void onClick(View v) { Intent intent=new Intent(MainActivity.this,Myservice.class); //启动服务要先传递一个intent switch (v.getId()) { case R.id.btn1: startService(intent);//启动服务 break; case R.id.btn2: stopService(intent);//终止服务 break; default: break; } } }; @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.main, menu); return true; } }
更多相关文章
- Android(安卓)Interface Definition Language (AIDL)
- Android(安卓)基础
- 隐式启动Activity 报ActivityNotFoundException
- android
- android > android 客户端 ,PHP 服务器端 HttpGet类和HttpPost类
- android (22)
- Android模拟器无法启动
- android studio 3.1 Android(安卓)Device Monitor 新的启动方式
- 启动模式详解