AES Crypto 在 Android(安卓)P（Android(安卓)9.0）被删除解决方案

开发工具：Android Studio

项目中若使用 SecureRandom.getInstance("SHA1PRNG", "Crypto") ，会给出以下警告：

The Crypto provider has been deleted in Android P (and was deprecated in Android N), so the code will crash. less... (Ctrl+F1)
The Crypto provider has been completely removed in Android P (and was deprecated in an earlier release). This means that the code will throw a NoSuchProviderException and the app will crash. Even if the code catches that exception at a higher level, this is not secure and should not be used.

即：Crypto provider 在 Android N（7.0）中已弃用，在Android P（9.0）中已删除。

附相关上下文参考代码：

byte[] lSeedBytes = "password".getBytes();
SecureRandom lSecureRandom = SecureRandom.getInstance("SHA1PRNG", "Crypto");
KeyGenerator lKeyGenerator = KeyGenerator.getInstance("AES");
lSecureRandom.setSeed(lSeedBytes);
lKeyGenerator.init(256, lSecureRandom);
SecretKey lSecretKey = lKeyGenerator.generateKey();
byte[] lResultEncoded = lSecretKey.getEncoded();

两种情况：

1， targetSdkVersion < 24 时，在Android P 以上的设备会出现： java.security.NoSuchProviderException: no such provider: Crypto

2，targetSdkVersion >= 24 时，在Android N 以上的设备会出现： java.security.NoSuchProviderException: no such provider: Crypto

此问题官方已经给出了参考方案： https://android-developers.googleblog.com/2018/03/cryptography-changes-in-android-p.html

但只给出了部分示例代码，对于存储，并未提供相关代码，如需要，可参考以下：

private static byte[] mSaltCache;
private static byte[] getSecretKeyEncoded(String password) throws Exception {
int iterationCount = 1000;
int saltLength = 32; // bytes; should be the same size as the output (256 / 8 = 32)
int keyLength = 256; // 256-bits for AES-256, 128-bits for AES-128, etc
if (mSaltCache == null || mSaltCache.length != saltLength) {
SharedPreferences lSP = Application.getInstance().getSharedPreferences("crypto_info", Context.MODE_PRIVATE);
String lSaveStr = lSP.getString("salt", "");
if (!TextUtils.isEmpty(lSaveStr)) {
mSaltCache = toArr(lSaveStr);
}
if (mSaltCache == null || mSaltCache.length != saltLength) {
byte[] salt = new byte[saltLength]; // Should be of saltLength
SecureRandom random = new SecureRandom();
random.nextBytes(salt);
lSP.edit().putString("salt", toStr(salt)).commit();
mSaltCache = salt;
}
}
KeySpec keySpec = new PBEKeySpec(password.toCharArray(), mSaltCache, iterationCount, keyLength);
SecretKeyFactory keyFactory = SecretKeyFactory.getInstance("PBKDF2WithHmacSHA1");
byte[] keyBytes = keyFactory.generateSecret(keySpec).getEncoded();
SecretKey key = new SecretKeySpec(keyBytes, "AES");
return key.getEncoded();
}

工具方法：

public static String toStr(byte[] aBytes) {
return toStr(aBytes, null);
}

public static String toStr(byte[] aBytes, String aSplit) {
if (aBytes == null) return null;
int lLength = aBytes.length;
if (lLength <= 0) return "";
if (TextUtils.isEmpty(aSplit)) aSplit = ",";
StringBuilder lSB = new StringBuilder();
for (int i = 0; i < lLength; i++) {
lSB.append(String.valueOf(aBytes[i]));
if (i != lLength - 1) lSB.append(aSplit);
}
return lSB.toString();
}

public static byte[] toArr(String aStr) {
return toArr(aStr, null, (byte) 0);
}

public static byte[] toArr(String aStr, String aSplit, byte aDefaultValue) {
if (TextUtils.isEmpty(aStr)) return null;
if (TextUtils.isEmpty(aSplit)) aSplit = ",";
String[] lItems = aStr.split(aSplit);
int lLength = lItems.length;
byte[] lResult = new byte[lLength];
for (int i = 0; i < lLength; i++) {
try {
lResult[i] = Byte.parseByte(lItems[i]);
} catch (Exception e) {
lResult[i] = aDefaultValue;
}
}
return lResult;
}

以上代码在官方示例基础上进行简单修改，仅供参考。

其他方案：

网上流传最多的一种方式为：

将：

SecureRandom.getInstance("SHA1PRNG", "Crypto")

修改为：

SecureRandom.getInstance("SHA1PRNG", new CryptoProvider());

public class CryptoProvider extends Provider {
public CryptoProvider() {
super("Crypto", 1.0, "HARMONY (SHA1 digest; SecureRandom; SHA1withDSA signature)");
put("SecureRandom.SHA1PRNG", "org.apache.harmony.security.provider.crypto.SHA1PRNG_SecureRandomImpl");
put("SecureRandom.SHA1PRNG ImplementedIn", "Software");
}
}

但此方式仅在 24 <= targetSdkVersion < 28 时，在 Android N 到 Android P 之间生效。

原文地址： https://blog.csdn.net/u011859715/article/details/83784238

尊重原创，转载请声明出处，谢谢！

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