Android(安卓)NoteX Q9: PopupWindow setOutsideTouchable 失效？

设置为true后点击外部还是会被dismiss掉，这是为什么？

/** * Controls whether the pop-up will be informed of touch events outside * of its window.  This only makes sense for pop-ups that are touchable * but not focusable, which means touches outside of the window will * be delivered to the window behind.  The default is false.
 * * If the popup is showing, calling this method will take effect only * the next time the popup is shown or through a manual call to one of * the {@link #update()} methods.
 * * @param touchable true if the popup should receive outside * touch events, false otherwise * * @see #isOutsideTouchable() * @see #isShowing() * @see #update() */public void setOutsideTouchable(boolean touchable) {     mOutsideTouchable = touchable;}

从官方api的解释来看，当focusable=false时，设置setOutsideTouchable才有意义。那么设置了focusable=true时，就没有意义，因为focusable=true会拿走焦点事件，outside拿不到焦点，则的outside的touch就无用处了。

那如何实现既设置focusable=true，也要外部(outside)点击不被dismiss呢？

var isForceDismiss = falseoverride fun dismiss() {     if (isForceDismiss) {     super.dismiss()isForceDismiss = true    }}

改写popupwindow的dismiss方法，做个逻辑判断即可。

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