Android腾讯微博开发之随机字符串与签名实现

Android腾讯微博开发入门之随机字符串与签名实现直接上代码 1、Utils类，包括签名和随机字符串 import java.util.Random; import javax.crypto.Mac; import javax.crypto.spec.SecretKeySpec; /** * * @author mrlixirong * * 2011-11-16 */ public class Utils { //签名 public static String getSignature(String baseString,String key){ String returnStr=""; Mac mac = null; byte[] byteHMAC = null; try { mac = Mac.getInstance("HmacSHA1"); SecretKeySpec spec = new SecretKeySpec(key.getBytes(), "HmacSHA1"); mac.init(spec); byteHMAC = mac.doFinal(baseString.getBytes()); returnStr = Base64Encoder.encode(byteHMAC); //returnStr=URLEncoder.encode(returnStr,ENCODING); } catch (Exception e1) { returnStr="error"; e1.printStackTrace(); } return returnStr; } /* * 获取随机字符串 * 实现方法很多，也很简单，但是对这种简单的东西，开发者有时候就是不想去敲键盘 * 但是不敲就做不下去，本来在此愿意成全和我一样有此烦恼的开发者 */ public static String getRandomString(int len){ String returnStr=""; char[] ch=new char[len]; Random rd=new Random(); for(int i=0;i<len;i++){ ch[i]=(char)(rd.nextInt(9)+97); } returnStr=new String(ch); return returnStr; } } 2、Base64Encoder public class Base64Encoder { private static final char last2byte = (char) Integer.parseInt("00000011", 2); private static final char last4byte = (char) Integer.parseInt("00001111", 2); private static final char last6byte = (char) Integer.parseInt("00111111", 2); private static final char lead6byte = (char) Integer.parseInt("11111100", 2); private static final char lead4byte = (char) Integer.parseInt("11110000", 2); private static final char lead2byte = (char) Integer.parseInt("11000000", 2); private static final char[] encodeTable = new char[]{'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '+', '/'}; public static String encode(byte[] from) { StringBuffer to = new StringBuffer((int) (from.length * 1.34) + 3); int num = 0; char currentByte = 0; for (int i = 0; i < from.length; i++) { num = num % 8; while (num < 8) { switch (num) { case 0: currentByte = (char) (from[i] & lead6byte); currentByte = (char) (currentByte >>> 2); break; case 2: currentByte = (char) (from[i] & last6byte); break; case 4: currentByte = (char) (from[i] & last4byte); currentByte = (char) (currentByte << 2); if ((i + 1) < from.length) { currentByte |= (from[i + 1] & lead2byte) >>> 6; } break; case 6: currentByte = (char) (from[i] & last2byte); currentByte = (char) (currentByte << 4); if ((i + 1) < from.length) { currentByte |= (from[i + 1] & lead4byte) >>> 4; } break; } to.append(encodeTable[currentByte]); num += 6; } } if (to.length() % 4 != 0) { for (int i = 4 - to.length() % 4; i > 0; i--) { to.append("="); } } return to.toString(); } }

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