listview使用ArrayAdapter显示文字

package com.example.listview_6;import java.util.ArrayList;import java.util.List;import android.app.Activity;import android.os.Bundle;import android.view.Menu;import android.view.MenuItem;import android.widget.ArrayAdapter;import android.widget.ListView;public class MainActivity extends Activity {private ListView listView1;@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setContentView(R.layout.activity_main);listView1 = (ListView) findViewById(R.id.listView1);List list = new ArrayList();list.add("aa");list.add("bb");list.add("cc");list.add("dd");list.add("ee");list.add("ff");String[] arr = { "aa", "bb", "cc" ,"dd","ee","ff","gg","hh","ii","jj"};// //正确//String[] arr2 = new String[5];// 正确 //定义维数和数组初始化不能同时进行// String[] arr4 = new String{"aa","bb","cc"};错误// String[] arr3 = new String[5]{"aa","bb","cc"};//错误///如果提供了数组初始化操作，则不能定义维表达式// ArrayAdapter adapter = new ArrayAdapter(this, android.R.layout.item, objects)//错误只有一个主布局，不需要条目布局，simple_expandable_list_item_1是系统自带的布局////第一种方法：//ArrayAdapter adapter = new ArrayAdapter(this,android.R.layout.simple_expandable_list_item_1, arr);///第二种方法ArrayAdapter  adapter = new ArrayAdapter(this, android.R.layout.simple_list_item_1, list);//最后一个参数是List或String[]均可listView1.setAdapter(adapter);}}

如果ListView一行是TextView,可以采用ArrayAdapter来实现，不用创建BaseAdapter

另外这是我个人开发的App，欢迎下载和好评，V1.5.0版本正在努力开发中......

http://www.wandoujia.com/apps/com.example.viewpager_3

更多相关文章

随机推荐