Android(安卓)拷贝Asset目录下文件或者文件夹
16lz
2021-01-26
项目中需要拷贝Asset目录下的所有文件，因为Asset目录是只读的，操作起来不是很方便，上网搜了一些方法并不是很有效，记录一下最后的解决方案：
//path - asset下文件（夹）名称 destinationPath - 目的路径`private void copyAssetFile(String path,String destinationPath) { AssetManager assetManager = mContext.getAssets(); String assets[] = null; try { Log.i("tag", "copyFileOrDir() "+path); assets = assetManager.list(path); if (assets.length == 0) { copyFile(path,destinationPath); } else { String fullPath = destinationPath + path; Log.i("tag", "path="+fullPath); File dir = new File(fullPath); if (!dir.exists() && !path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit")) if (!dir.mkdirs()) Log.i("tag", "could not create dir "+fullPath); for (int i = 0; i < assets.length; ++i) { String p; if (path.equals("")) p = ""; else p = path + "/"; if (!path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit")) copyAssetFileOrDir( p + assets[i],destinationPath); } } } catch (IOException ex) { Log.e("tag", "I/O Exception", ex); }}``private void copyFile(String filename,String destinationPath) { AssetManager assetManager = mContext.getAssets(); InputStream in = null; OutputStream out = null; String newFileName = null; try { Log.i("tag", "copyFile() "+filename); in = assetManager.open(filename); newFileName = destinationPath + filename; out = new FileOutputStream(newFileName); byte[] buffer = new byte[1024]; int read; while ((read = in.read(buffer)) != -1) { out.write(buffer, 0, read); } in.close(); in = null; out.flush(); out.close(); out = null; } catch (Exception e) { Log.e("tag", "Exception in copyFile() of "+newFileName); Log.e("tag", "Exception in copyFile() "+e.toString()); }}`更多相关文章
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