Android(安卓)模糊搜索rawquery bind or column index out of range: handle 0x2fb180 报错
16lz
2021-01-25
做模糊搜索时，出现了 bind or column index out of range: handle 0x2fb180 报错
public Cursor getTitle(String word) throws SQLException
{
String sql = "select * from contentinfo1 where title =? ";
Cursor cursor = db.rawQuery(sql, new String[] {word});
return cursor;
｝
实现精确匹配后，依葫芦画瓢的想制作模糊搜索，套用了SQL语句，不料出错
public Cursor getTitle(String word) throws SQLException
{
String sql = "select * from contentinfo1 where title like '%"+word+"%'";
Cursor cursor = db.rawQuery(sql, new String[] {word});
return cursor;
｝
解决方法：
public Cursor getTitle(String word) throws SQLException
{
String sql = "select * from contentinfo1 where title like '%"+word+"%'";
Cursor cursor = db.rawQuery(sql,null);
return cursor;
｝
原因：更改语句之后用了+word+而非占位符 ？， 所以rawQuery第二个参数不知道和哪个对应故出现报错
进一步修改方案可以参照
http://stackoverflow.com/questions/5716543/android-sqliteexception-bind-or-column-index-out-of-range-problem
需要将第二个rawquery参数更改为NULL
public Cursor getTitle(String word) throws SQLException
{
String sql = "select * from contentinfo1 where title =? ";
Cursor cursor = db.rawQuery(sql, new String[] {word});
return cursor;
｝
实现精确匹配后，依葫芦画瓢的想制作模糊搜索，套用了SQL语句，不料出错
public Cursor getTitle(String word) throws SQLException
{
String sql = "select * from contentinfo1 where title like '%"+word+"%'";
Cursor cursor = db.rawQuery(sql, new String[] {word});
return cursor;
｝
解决方法：
public Cursor getTitle(String word) throws SQLException
{
String sql = "select * from contentinfo1 where title like '%"+word+"%'";
Cursor cursor = db.rawQuery(sql,null);
return cursor;
｝
原因：更改语句之后用了+word+而非占位符 ？， 所以rawQuery第二个参数不知道和哪个对应故出现报错
进一步修改方案可以参照
http://stackoverflow.com/questions/5716543/android-sqliteexception-bind-or-column-index-out-of-range-problem
需要将第二个rawquery参数更改为NULL
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