Android(安卓)定时让popupwindow消失

因为是在其他界面弹出的popupwindow，要在横屏切换回竖屏的时候，让popupwindow自动消失，因为弹出popupwindow是普通的类，没有监听横竖屏的函数，所以想到了使用定时器，定时3秒之后如果用户没有操作就让popupwindow消失，代码如下：

// 创建弹出窗口popupMenu = new PopupWindow(view, sourceView.getWidth() * 2,LayoutParams.WRAP_CONTENT + 200);ColorDrawable cd = new ColorDrawable(R.color.white);popupMenu.setBackgroundDrawable(cd);popupMenu.update();popupMenu.setInputMethodMode(PopupWindow.INPUT_METHOD_NEEDED);popupMenu.setTouchable(true); // 设置popupwindow可点击popupMenu.setOutsideTouchable(true); // 设置popupwindow外部可点击popupMenu.setFocusable(true); // 获取焦点ColorDrawable dw = new ColorDrawable(0x00);popupMenu.setBackgroundDrawable(dw);popupMenu.setTouchInterceptor(new View.OnTouchListener() {@Overridepublic boolean onTouch(View v, MotionEvent event) {if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {popupMenu.dismiss();return true;}timer.start();return false;}});}CountDownTimer timer = new CountDownTimer(3000, 10) {@Overridepublic void onTick(long millisUntilFinished) {}@Overridepublic void onFinish() {popupMenu.dismiss();}};@Overridepublic PopupWindow createPupupWindow() {return popupMenu;}@Overridepublic void showPopupMenu() {if (popupMenu != null && popupMenu.isShowing()) {popupMenu.dismiss();} else {popupMenu.showAsDropDown(sourceView, -sourceView.getWidth() / 2, 0);timer.start();}}

关键点是使用CountDownTimer类，来进行定时，已经全部封装好了，不要去考虑子线程无法去改变UI界面的问题，还是非常好用的。

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