Android使用DOM方式解析XML

1．介绍
在Android系统中很多信息及配置文件都是以xml格式存储的，Android系统也提供SAX和DOM两种方式来解析XML文件，下面介绍其中比较简单的DOM方式。

2．例程

1)功能
解析xml文件内容，并显示在程序界面上

2)关键字
Android, xml, dom, 解析

3)可从此处下载可独立运行的代码
http://download.csdn.net/detail/xieyan0811/4117455

4)核心代码及说明

package com.demo.xml;

import android.app.Activity;

import android.os.Bundle;

import android.widget.TextView;

import android.widget.LinearLayout;

import android.util.Log;

import org.w3c.dom.Element;

import org.w3c.dom.NodeList;

import org.w3c.dom.Document;

import javax.xml.parsers.DocumentBuilder;

import javax.xml.parsers.DocumentBuilderFactory;

import javax.xml.parsers.ParserConfigurationException;

import java.io.IOException;

import java.io.InputStream;

public class MyXmlActivity extends Activity {

private String TAG ="demo";

@Override

public voidonCreate(Bundle savedInstanceState) {

super.onCreate(savedInstanceState);

setContentView(R.layout.main);

parseXml();

}

private voidparseXml() {

int i, j;

TextViewtext;

LinearLayoutlinear = new LinearLayout(this);

linear.setOrientation(LinearLayout.VERTICAL);

DocumentBuilderFactorydocFactory = DocumentBuilderFactory

.newInstance();

DocumentBuilderdocBuilder;

Document doc= null;

InputStreaminStream = null;

try {

docBuilder= docFactory.newDocumentBuilder();

inStream= this.getResources().getAssets().open("test.xml");

doc= docBuilder.parse(inStream);

ElementrootEle = doc.getDocumentElement();

NodeListquestionNode = rootEle.getElementsByTagName("submenu");

intsubCount = questionNode.getLength();

for(i = 0; i < subCount; i++) {

ElementsubEle = (Element) questionNode.item(i);

StringsubTitle = subEle.getAttribute("title");

Log.e(TAG,"title = " + subTitle);

text= new TextView(this);

text.setText(subTitle);

linear.addView(text);

NodeListitemNode = subEle.getElementsByTagName("item");

intitemCount = itemNode.getLength();

for(j = 0; j < itemCount; j++) {

ElementoptionEle = (Element) itemNode.item(j);

Stringdesc = optionEle.getAttribute("desc");

Stringpos = optionEle.getAttribute("pos");

Log.e(TAG,"desc = " + desc + ", pos = " + pos);

text= new TextView(this);

text.setText(desc+ ", " + pos);

linear.addView(text);

}

} catch(ParserConfigurationException e1) {

e1.printStackTrace();

} catch(IOException e) {

e.printStackTrace();

} catch(Exception e) {

e.printStackTrace();

}

setContentView(linear);

}

};

// xml 内容

<?xml version="1.0" encoding="utf-8" ?>

<menu>

<submenutitle="test1">

<item desc="item1" pos="012" />

<item desc="item2" pos="123" />

</submenu>

<submenutitle="test2">

<item desc="item3" pos="234" />

<item desc="item4" pos="456" />

</submenu>
<submenu title="test3">

<item desc="item5" pos="567" />

<item desc="item6" pos="678" />

<item desc="item7" pos="789" />

</submenu>

</menu>

3．参考

1)SAX教程：http://www.2cto.com/kf/201101/81739.html

(转载请注明出处)

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