在android中玩转wcf
16lz
2021-01-23
package com.cjt_pc.vehicleregulatoryestimate.utils;import android.app.Activity;import org.ksoap2.SoapEnvelope;import org.ksoap2.serialization.SoapObject;import org.ksoap2.serialization.SoapSerializationEnvelope;import org.ksoap2.transport.HttpTransportSE;import org.xmlpull.v1.XmlPullParserException;import java.io.IOException;import java.util.HashMap;import java.util.LinkedHashMap;/** * Created by cjt-pc on 2015/7/8. * Email:879309896@qq.com */public class SoapUtil implements SoapConfig { public static SoapObject postSoapRequest(String method) { return postSoapRequest(method, null); } public static SoapObject postSoapRequest(String method, LinkedHashMap<String, Object> properties) { String nameSpace = NAMESPACE; String url = getUrl(method); String soapAction = getAction(method); // 初始化传入参数soapObject SoapObject soapObject = new SoapObject(nameSpace, method); for (LinkedHashMap.Entry<String, Object> entry : properties.entrySet()) { soapObject.addProperty(entry.getKey(), entry.getValue()); } // 设置版本和指定信封envelope的数据soapObject SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER10); envelope.bodyOut = soapObject; envelope.dotNet = true; // 采用webservice协议发送请求 HttpTransportSE transport = new HttpTransportSE(url); transport.debug = true; try { transport.call(soapAction, envelope); } catch (final Exception e) { e.printStackTrace(); } // 接受服务端返回的数据，取其child SoapObject object = (SoapObject) ((SoapObject) envelope.bodyIn).getProperty(0); return object == null ? null : object; } /** * 根据传回的方法名返回指定的url * * @param methodName 方法名 * @return 访问地址 */ private static String getUrl(String methodName) { switch (methodName) { case LOGININ_METHOD: return URL_1; case GET_RW_LIST_METHOD: return URL_2; case GET_HBBZ_METHOD: return URL_1; case GET_PP_METHOD: return URL_2; case GET_CXI_METHOD: return URL_2; case GET_CXING_METHOD: return URL_2; case GET_UPLOAD_IMG_METHOD: return URL_3; case UPLOAD_PHOTO_METHOD: return URL_3; case SAVE_PGRW_METHOD: return URL_2; } return null; } /** * 根据传回的方法名返回指定的action * * @param methodName 方法名 * @return 访问action */ private static String getAction(String methodName) { switch (methodName) { case LOGININ_METHOD: return LOGININ_ACTION; case GET_RW_LIST_METHOD: return GET_RW_LIST_ACTION; case GET_HBBZ_METHOD: return GET_HBBZ_ACTION; case GET_PP_METHOD: return GET_PP_ACTION; case GET_CXI_METHOD: return GET_CXI_ACTION; case GET_CXING_METHOD: return GET_CXING_ACTION; case GET_UPLOAD_IMG_METHOD: return GET_UPLOAD_IMG_ACTION; case UPLOAD_PHOTO_METHOD: return UPLOAD_PHOTO_ACTION; case SAVE_PGRW_METHOD: return SAVE_PGRW_ACTION; } return null; }}SoapConfig的代码我就不贴了，都是些地址配置，这个工具类有点通杀的感觉，那接下来就看看怎么用了。
public class LoginInTask extends AsyncTask<Void, Void, SoapObject> { String account, pwd; public LoginInTask(String account, String pwd) { this.account = account; this.pwd = pwd; } @Override protected SoapObject doInBackground(Void... params) { editor = preferences.edit(); editor.putString("account", account); editor.apply(); LinkedHashMap<String, Object> properties = new LinkedHashMap<>(); properties.put("TrueName", account); properties.put("Pwd", pwd); return SoapUtil.postSoapRequest("LoginIn", properties); } @Override protected void onPostExecute(SoapObject soapObject) { if (soapObject.getPropertyCount() == 0) { failedLogin(); } else { // 登陆成功 succeedLogin(); } } }为什么要用LinkedHashMap而不是HashMap？
貌似wcf传输要按照一定的顺序，否则不通！
为什么使用AsyncTask而不是手动开启线程？
这样模块化了代码，清晰易懂，并且与界面交互较为简单。