Android开机自动启动程序设置

Android开机自启动

1.定义一个BroadcastReceiver

Java代码

publicclassBootReceiverextendsBroadcastReceiver{
publicvoidonReceive(Contextctx,Intentintent){
Log.d("BootReceiver","systembootcompleted");
//startactivity
Stringaction="android.intent.action.MAIN";
Stringcategory="android.intent.category.LAUNCHER";
Intentmyi=newIntent(ctx,CustomDialog.class);
myi.setAction(action);
myi.addCategory(category);
myi.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
ctx.startActivity(myi);
//startservice
Intents=newIntent(ctx,MyService.class);
ctx.startService(s);
}
}

public class BootReceiver extends BroadcastReceiver {public void onReceive(Context ctx, Intent intent) {Log.d("BootReceiver", "system boot completed");//start activityString action="android.intent.action.MAIN";String category="android.intent.category.LAUNCHER";Intent myi=new Intent(ctx,CustomDialog.class);myi.setAction(action);myi.addCategory(category);myi.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);ctx.startActivity(myi);//start serviceIntent s=new Intent(ctx,MyService.class);ctx.startService(s);}}

2.配置Receiver的许可,允许接收系统启动消息，在AndroidManifest.xml中：

Xml代码

<uses-permissionandroid:name="android.permission.RECEIVE_BOOT_COMPLETED"/>

<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED"/>

3.配置Receiver,可以接收系统启动消息，在AndroidManifest.xml中

Xml代码

<receiverandroid:name=".app.BootReceiver">
<intent-filter>
<actionandroid:name="android.intent.action.BOOT_COMPLETED"/>
<categoryandroid:name="android.intent.category.HOME"/>
</intent-filter>
</receiver>

        <receiver android:name=".app.BootReceiver">        <intent-filter>        <action android:name="android.intent.action.BOOT_COMPLETED"/>                <category android:name="android.intent.category.HOME" />        </intent-filter>        </receiver>

4.启动模拟器，可以看到系统启动后，弹出一个对话框。

Android开机自启动

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