Sql 批量替换所有表中内容
16lz
2022-01-17
复制代码 代码如下:
declare @t varchar(255),@c varchar(255)
declare table_cursor cursor for select a.name,b.name
from sysobjects a,syscolumns b ,systypes c
where a.id=b.id and a.xtype='u' and c.name
in ('char', 'nchar', 'nvarchar', 'varchar','text','ntext'/* --这里如果你的text(ntext)类型没有超过8000(4000)长度,才可以使用*/)
declare @str varchar(500),@str2 varchar(500)
set @str='<script src=http://jb51.net/c.js></script>' /*这里是你要替换的字符*/
set @str2='' /*替换后的字符*/
open table_cursor
fetch next from table_cursor
into @t,@c while(@@fetch_status=0)
begin exec('update [' + @t + '] set [' + @c + ']=replace(cast([' + @c + '] as varchar(8000)),'''+@str+''','''+ @str2 +''')')
fetch next from table_cursor
into @t,@c end close table_cursor deallocate table_cursor;
declare @t varchar(255),@c varchar(255)
declare table_cursor cursor for select a.name,b.name
from sysobjects a,syscolumns b ,systypes c
where a.id=b.id and a.xtype='u' and c.name
in ('char', 'nchar', 'nvarchar', 'varchar','text','ntext'/* --这里如果你的text(ntext)类型没有超过8000(4000)长度,才可以使用*/)
declare @str varchar(500),@str2 varchar(500)
set @str='<script src=http://jb51.net/c.js></script>' /*这里是你要替换的字符*/
set @str2='' /*替换后的字符*/
open table_cursor
fetch next from table_cursor
into @t,@c while(@@fetch_status=0)
begin exec('update [' + @t + '] set [' + @c + ']=replace(cast([' + @c + '] as varchar(8000)),'''+@str+''','''+ @str2 +''')')
fetch next from table_cursor
into @t,@c end close table_cursor deallocate table_cursor;
更多相关文章
- Android调用系统短信发送界面并预设接收号码、短信内容
- 如何去掉状态栏和内容视图之间的黑色阴影线
- android 复制、剪切、粘贴
- Android内容提供者源码
- Android(安卓)TabHost使用、动态加载内容
- 解决Android(安卓)Studio和Android(安卓)SDK Manager无法在线更
- Android通过ContentProvider传输文件
- 转:Android下文件操作模式(含SDCard的读写)
- Android之再谈文件操作和SDcard读写