如果在两个模式中存在具有相似名称的删除表

I use this command to drop a table in sql-server 2008

我使用此命令删除sql-server 2008中的表

IF EXISTS(SELECT name FROM [DBName]..sysobjects WHERE name = N'TableName' AND xtype='U')
DROP TABLE [DBName].[SchemaName].[TableName];

But now I have 2 tables with same name in different schema:

但是现在我在不同的模式中有2个具有相同名称的表:

[DBName].[Schema1].[Members]

And

 [DBName].[Schema2].[Members]

So, what is your suggestion for check if exist this tables? How can I check table names with schema?

那么,你有什么建议检查这些表是否存在?如何使用模式检查表名?

UPDATE:

OK, there is 3 different answers and all of them worked, so I don't know which one is better, does any one know about use object_id or sys.tables?

好的,有3个不同的答案,所有这些都有效,所以我不知道哪一个更好,有没有人知道使用object_id或sys.tables?

4 个解决方案

#1

IF EXISTS(
  SELECT * 
  FROM [DBName].sys.tables t
  JOIN [DBName].sys.schemas s
    ON t.SCHEMA_ID = s.schema_id
  WHERE 
      t.name = N'TableName' AND t.type='U' 
  AND s.NAME = 'SchemaName'
)
  DROP TABLE [DBName].[SchemaName].[TableName];

Update:

object_id in sys.tables is the same as object_id in sysobjects for the same table. And is completely the same as function OBJECT_ID returns for the same table name. See the following illustrating examples.

sys.tables中的object_id与同一表的sysobjects中的object_id相同。并且与函数OBJECT_ID完全相同,返回相同的表名。请参阅以下说明示例。

So, you may simplify the query:

因此,您可以简化查询:

IF exists 
  (
    SELECT * 
    FROM DBName.sys.tables 
    WHERE object_id = OBJECT_ID('[DBName].[SchemaName].[TableName]')
    AND type = 'U'
  )
  DROP TABLE [DBName].[SchemaName].[TableName];

or in this way:

或以这种方式:

IF exists 
  (
    SELECT * 
    FROM DBName.sys.objects
    WHERE object_id = OBJECT_ID('[DBName].[SchemaName].[TableName]')
    AND type = 'U'
  )
  DROP TABLE [DBName].[SchemaName].[TableName];

or for sql2000-styled tables:

或者对于sql2000样式的表:

IF exists 
  (
    SELECT * 
    FROM DBName..sysobjects
    WHERE object_id = OBJECT_ID('[DBName].[SchemaName].[TableName]')
    AND xtype = 'U'
  )
  DROP TABLE [DBName].[SchemaName].[TableName];

4 个解决方案

#1

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