mysql在一个表上进行多个分组

I have one table job_result

我有一个表job_result

CREATE TABLE job_result  (
  node varchar(20) DEFAULT NULL,
  jobId int(10) DEFAULT NULL,
  subResult int(1) DEFAULT NULL
)

The table contains many nodes.

该表包含许多节点。

Each node has many jobId.

每个节点都有许多jobId。

Each jobId has many subResults (usually less than 10).

每个jobId都有许多subResults(通常少于10个)。

Some example data provided

提供了一些示例数据

insert into job_result values ('A', 14, 0);
insert into job_result values ('A', 15, 0);
insert into job_result values ('A', 16, 1);
insert into job_result values ('A', 17, 0);
insert into job_result values ('A', 18, 1);
insert into job_result values ('A', 19, 1);
insert into job_result values ('A', 20, 0);


insert into job_result values ('B', 1, 0);
insert into job_result values ('B', 2, 0);
insert into job_result values ('B', 3, 1);
insert into job_result values ('B', 4, 1);
insert into job_result values ('B', 5, 1);
insert into job_result values ('B', 6, 1);
insert into job_result values ('B', 7, 1);


insert into job_result values ('C', 10, 0);
insert into job_result values ('C', 11, 0);
insert into job_result values ('C', 12, 0);
insert into job_result values ('C', 13, 0);
insert into job_result values ('C', 14, 0);
insert into job_result values ('C', 15, 0);
insert into job_result values ('C', 16, 0);

I want a query to give me a "health check" on each node to see if a node has had X consecutively failed jobs. A failed job is a jobId that have at least one non-zero result.

我想要一个查询,在每个节点上给我一个“运行状况检查”,看看一个节点是否有X个连续失败的作业。失败的作业是至少有一个非零结果的jobId。

SELECT node, jobId, SUM(subResult) res
FROM job_result WHERE node = 'A' 
GROUP BY jobId 
ORDER BY jobId desc 
LIMIT 5

This gives me the last 5 job's result on node A, where 0 indicates a good job.

这给了我节点A上最后5个作业的结果,其中0表示一个好工作。

+------+---------+------+
| node | jobId   | res  |
+------+---------+------+
| A    |   20    |   0  |
| A    |   19    |   1  |
| A    |   18    |   1  |
| A    |   17    |   0  |
| A    |   16    |   1  |

Then I need to sum and group the results into one row per node and I got this far:

然后我需要对每个节点的结果进行求和并将其分组,我得到了这个:

SELECT node, SUM(I.res) res
FROM
(SELECT node, sum(subResult) res
FROM job_result WHERE node = 'A' 
GROUP BY jobId 
ORDER BY jobId desc 
LIMIT 5) I

+------+------+
| node | res  |
+------+------+
| A    |  3   |

My question is: How can I expand this query to return one row per node? I have tried for several days with correlated sub queries and joins, but I always fail due to the inner select cannot see which node to select on. And when that is in place, I will work on changing LIMIT 5 to a dynamic value.

我的问题是:如何扩展此查询以返回每个节点一行?我已经尝试了几天与相关的子查询和连接,但我总是失败,因为内部选择无法看到选择哪个节点。当它到位时,我将努力将LIMIT 5更改为动态值。

Desired result would be like

期望的结果就像

+------+------+
| node | res  |
+------+------+
| A    |  3   |
| B    |  0   |
| C    |  1   |
| E    |  0   |

One row for each node, with the right column showing number of fails

每个节点一行,右列显示失败次数

Please advise!

1 个解决方案

#1

In MySQL, on a large table, the best approach to getting the last 5 is to use variables to enumerate the results. The rest is just aggregation:

在MySQL中,在大型表上,获得最后5个的最佳方法是使用变量来枚举结果。其余的只是聚合:

SELECT node, SUM(subr > 0) as numfails
FROM (SELECT node, jobid, subr,
             (@rn := if(@n = node, @rn + 1,
                        if(@n := node, 1, 1)
                       )
             ) as rn
      FROM (SELECT node, jobid,
                   SUM(subresult) as subr
            FROM job_result jr
            GROUP BY node, jobid
           ) jr CROSS JOIN
           (SELECT @n := '', @rn := 0) init
      ORDER BY node, jobid desc
     ) nr
WHERE rn <= 5
GROUP BY node;

1 个解决方案

#1

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