如何只从$_SERVER['HTTP_REFERER']中选择根域?
I want to have a 404 page that can detect if a user has come to that page either via my site, via my shortened URL or via another site, and I am making it using PHP. I am slowly getting to grips with PHP and this may well be a simple question, but I am quite tired to be honest and have no caffeine in my system, and I am wanting to tie up any loose ends in my portfolio as soon as possible.
我想要一个404页面，它可以检测用户是否通过我的站点，通过我的缩短的URL或者通过其他站点访问该页面，我使用的是PHP。我正在慢慢地掌握PHP，这可能是一个简单的问题，但说实话我很累，我的系统中没有咖啡因，我想尽快解决我的投资组合中的任何问题。
I have found the $_SERVER['HTTP_REFERER']; PHP variable gives me the entire URL, which is a start. Is there a way that this can give me only the root domain, either via another variable or a function, bearing in mind that some referrers may be using http:// and some https:// (so simply starting from the seventh character would not always work)? That way, I can match the URL based on two (or more) predefined addresses and produce the content that relates to that domain.
我找到了$_SERVER['HTTP_REFERER'];PHP变量为我提供了整个URL，这是一个开始。是否有一种方法可以只给我根域，通过另一个变量或一个函数，记住一些引用者可能使用http://和https://(所以仅仅从第7个字符开始并不总是有效)?这样，我就可以根据两个(或多个)预定义地址匹配URL，并生成与该域相关的内容。
3 个解决方案
#1
40
parse_url($_SERVER['HTTP_REFERER'], PHP_URL_HOST)
See http://php.net/manual/en/function.parse-url.php.
见http://php.net/manual/en/function.parse-url.php。
Note though that the referer is terrifically easy to spoof, so it's hardly reliable.
请注意，尽管引用者非常容易被欺骗，所以它几乎不可靠。
更多相关文章
- php如何跨站抓取别的站点的页面的补充
- (T_ENCAPSED_AND_WHITESPACE)，期望标识符(T_STRING)或变量(T_VARI
- php static静态变量及方法详解
- 如何将结果输入变量MYSQL
- thinkphp环境变量.env配置
- smarty模板引擎变量的传递方法
- PHP会话变量没有转移到我登录的页面，但是会话ID是
- php变量函数，回调函数
- PHP 站点相对包含，路径的问题解决方法（include,require)