如何在不更改其键值的情况下删除数组的第一个元素？

I have an array in php

我在php中有一个数组

<?php
$array=array("a"=>"123","b"=>"234","c"=>"345");
array_shift($array);
//array("0"=>"234","1"=>"345");
?>

If I use this function, then key value gets changed. I want my key value to remain the same. How can I remove first element without affecting array key values. My answer should be like

如果我使用此功能，则键值会发生变化。我希望我的键值保持不变。如何在不影响数组键值的情况下删除第一个元素。我的回答应该是这样的

array("b"=>"234","c"=>"345");

Note:Please do not use foreach(); I want to do this by existing array functions in php

注意：请不要使用foreach（）;我想通过php中现有的数组函数来做到这一点

array_splice function is working for above array. But consider the below array

array_splice函数适用于上面的数组。但请考虑以下数组

<?php
$array = Array
(
    '39' => Array
        (
            'id' => '39',
            'field_id' => '620'

        ),

    '40' => Array
        (
            'id' => '40',
            'field_id' => '620',
            'default_value' => 'rrr',

));

array_splice($array, 0, 1);
print_r($array);
?>

It is showing answer as follows:

它的答案如下：

Array ( [0] => Array ( [id] => 40 [field_id] => 620 [default_value] => rrr ) )

May I know the reason?? Will array_splice() work only for single dimensional array?? Now key value is reset...

我可以知道原因吗？ array_splice（）只适用于单维数组吗？现在键值被重置......

4 个解决方案

#1

In case you do not know what the first item's key is:

如果你不知道第一项的关键是什么：

// Make sure to reset the array's current index
reset($array);

$key = key($array);
unset($array[$key]);

4 个解决方案

#1

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