添加到数据库后，保持在同一页面而不刷新它

I have PHP web page where I need to insert some information to my database. When insert is done, it refresh the same page. But I've been told that this process is not practical because you are loading all HTML, CSS, and JS of your page every time. And I should you AJAX to do that.

我有PHP网页,我需要在我的数据库中插入一些信息。插入完成后,刷新同一页面。但我被告知这个过程不实用,因为您每次都会加载页面的所有HTML,CSS和JS。我应该AJAX这样做。

I search for it, and tried this code:

我搜索它,并尝试了这段代码:

$("#insert").click(function(){
 //get the form values
 var selectType = $('#selectW').val();
 var selectcom = $('#select_at').val();
 var pay = $('#pay').val();     
 var facture = $('#facture').val();     
 var selectcur = $('#select').val(); 

 //make the postdata
 //var postData = 'username='+username+'&name='+name+'&brand='+brand;

 //call your input.php script in the background, when it returns it will call the success function if the request was successful or the error one if there was an issue (like a 404, 500 or any other error status)

     $.ajax({
        url : "insert.php",
        type: "POST",
        data : postData,
        success: function(data,status, xhr)
        {
            //if success then just output the text to the status div then clear the form inputs to prepare for new data
            $("#section2").html(data);
            $('#pay').val('');
            $('#selectcur').val('');
        },
        error: function (jqXHR, status, errorThrown)
        {
            //if fail show error and server status
            $("#section2").html('there was an error ' + errorThrown + ' with status ' + textStatus);
        }
    });// JavaScript Document

And here is my PHP-PDO code where I removed the header lines and replaced them with echo("something"):

这是我的PHP-PDO代码,我删除了标题行并用echo(“something”)替换它们:

if(isset($_POST['insert'])){
    $selectOpt1 = $_POST['currency'];
    if($selectOpt1=="9"){
        $type = $_POST['type'];
        $provider = $_POST['alfa_touch'];
        $pay = $_POST['pay'];
        $facture = $_POST['facture'];
        try{
            $query = "INSERT INTO sales
            (type, provider, pay, facture, date_now, time_now) 
            VALUES
            (:type, :provider, :pay, :facture, :date, now())";
            $stmt = $conn->prepare($query);
            $stmt->bindValue(":type", $type);
            $stmt->bindValue(":provider", $provider);
            $stmt->bindValue(":pay", $pay);  
            $stmt->bindValue(":facture", $facture);
            $stmt->bindValue(":date", date("y-m-d"));
            $count = $stmt->execute();
            //header("location: home.php");
            echo ("Done");
        }
        catch(PDOException $e) {
            echo $e->getMessage();
            //header("location: ../pages/insert_false.php?id=".$projid);
            print_r($conn->errorInfo());

        }


    }
}

Now, when I click on insert button, the data are added correctly to MySQL database, but, the app stay in insert.php and echo Done. What I need is to stay in the same page. Any help is appreciated.

现在,当我点击插入按钮时,数据被正确添加到MySQL数据库,但是,应用程序保留在insert.php和echo Done中。我需要的是留在同一页面。任何帮助表示赞赏。

EDIT

$("#insert").click(function(){
 //get the form values
 var selectType = $('#selectW').val();
 var selectcom = $('#select_at').val();
 var pay = $('#pay').val();     
 var facture = $('#facture').val();     
 var selectcur = $('#select').val(); 

 //make the postdata
 var postData = 'username='+username+'&name='+name+'&brand='+brand;

 //call your input.php script in the background, when it returns it will call the success function if the request was successful or the error one if there was an issue (like a 404, 500 or any other error status)

 $.ajax({
    url : "insert.php",
    type: "POST",
    data : postData,
    success: function(data,status, xhr)
    {
        //if success then just output the text to the status div then clear the form inputs to prepare for new data
        $("#section2").html(data);
        $('#pay').val('');
        $('#selectcur').val('');
    },
    error: function (jqXHR, status, errorThrown)
    {
        //if fail show error and server status
        $("#section2").html('there was an error ' + errorThrown + ' with status ' + textStatus);
    }

});
return false;
});// JavaScript Document

Still the same problem. And here is my HTML form:

还是一样的问题。这是我的HTML表单:

<form name="insertForm" action="insert.php" method="post">

    <tr>
        <td align="center">
          <select id="selectW" name="type">
            <option value="Choose">Choose</option>
            <option value="Dollars">Dollars</option>
            <option value="D & D">D & D</option>
            <option value="Cards">Cards</option>
            <option value="Phones">Phones</option>
            <option value="Acc">Acc</option>
            <option value="Bills">Bills</option>
          </select>
          <!--<select>
          <?php foreach($result5 as $rows){ ?>
            <option value="<?php echo $rows['item_name'] ?>"><?php echo $rows['item_name'] ?></option>
            <?php } ?>
          </select>-->
          </td>
        <td align="center"><select id="select_at" name="alfa_touch">
            <option value="Undefined">Not Required</option>
            <option value="Alfa">Alfa</option>
            <option value="Touch">Touch</option></select></td>
        <td align="center"><input type="text" id="pay" name="pay"/></td>
        <td align="center"><input type="text" id="facture" name="facture" placeholder="في حال دفع الفواتير عبر omt"/></td>
        <td align="center"><select id="select" name="currency">
            <option value="9">LBP</option>
            <option value="10">Dollars</option>
            </select></td>

        <td align="center"><input type="submit" id="insert" name="insert" value="insert" />

      </td>

      </tr>
      </form>

2 个解决方案

#1

Add preventDefault to your javascript function

将preventDefault添加到您的javascript函数中

    Function(e){

    e.preventDefault()

    ...

}

2 个解决方案

#1

更多相关文章

随机推荐