从另一个Python脚本调用Python脚本的最佳方式是什么?

I have a script named test1.py which is not in a module. It just has code that should execute when the script itself is run. There are no functions, classes, methods, etc. I have another script which runs as a service. I want to call test1.py from the script running as a service.

我有一个名为test1的脚本。它不在模块中。它只有运行脚本时应该执行的代码。没有函数、类、方法等等。我有另一个脚本作为服务运行。我想调用test1。py来自作为服务运行的脚本。

For example:

例如:

File test1.py

print "I am a test"
print "see! I do nothing productive."

File service.py

# Lots of stuff here
test1.py # do whatever is in test1.py

I'm aware of one method which is opening the file, reading the contents, and basically eval'ing it. I'm assuming there's a better way of doing this. Or at least I hope so.

我知道有一种方法是打开文件，读取内容，并基本上eval它。我假设有更好的方法。至少我希望如此。

8 个解决方案

#1

204

The usual way to do this is something like the following.

通常的做法是这样的。

test1.py

def some_func():
    print 'in test 1, unproductive'

if __name__ == '__main__':
    # test1.py executed as script
    # do something
    some_func()

service.py

import test1

def service_func():
    print 'service func'

if __name__ == '__main__':
    # service.py executed as script
    # do something
    service_func()
    test1.some_func()

File test1.py

File service.py

8 个解决方案

#1

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