是否可以使用argparse来捕获任意一组可选参数?

Is it possible to use argparse to capture an arbitrary set of optional arguments?

For example both the following should be accepted as inputs:

例如，下列两项应被接受为输入:

python script.py required_arg1 --var1 value1 --var2 value2 --var3 value3

python script.py required_arg1 --varA valueA --var2 value2 --varB valueB

a priori I don't know what optional arguments would be specified receive but would handle them accordingly.

事先我不知道会指定哪些可选参数接收，但会相应地处理它们。

2 个解决方案

#1

This is kind of a hackish way, but it works very well:

这是一种陈腐的方法，但效果很好:

Check, which arguments are not added and add them

检查，哪些参数没有添加并添加

parser=argparse.ArgumentParser()
parser.add_argument("foo")
parser.add_argument("-bar", type=int)
#parser can have any arguments, whatever you want!

parsed, unknown = parser.parse_known_args() #this is an 'internal' method
# which returns 'parsed', the same as what parse_args() would return
# and 'unknown', the remainder of that
# the difference to parse_args() is that it does not exit when it finds redundant arguments

for arg in unknown:
    if arg.startswith(("-", "--")):
        #you can pass any arguments to add_argument
        parser.add_argument(arg, type=<your type>, ...)

args=parser.parse_args()

For example:

例如:

python arbitrary_parser.py ha -bar 12 -lol huhu -rofl haha

Then the result would be

那么结果就是

args = Namespace(bar=12, foo='ha', lol='huhu', rofl='haha')

2 个解决方案

#1

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