在Python中使用正则表达式匹配的字符串周围添加括号
16lz
2021-01-22
Given a regex and a string s, I would like to generate a new string in which any substring of s matched by the regex is surrounded by parentheses.
给定正则表达式和字符串s,我想生成一个新的字符串,其中正则表达式匹配的s的任何子字符串都被括号括起来。
For example: My original string s is "Alan Turing 1912-1954" and my regex happens to match "1912-1954". The newly generated string should be "Alan Turing (1912-1954)".
例如:我的原始字符串s是“Alan Turing 1912-1954”,我的正则表达式恰好匹配“1912-1954”。新生成的字符串应为“Alan Turing(1912-1954)”。
1 个解决方案
#1
9
Solution 1:
>>> re.sub(r"\d{4}-\d{4}", r"(\g<0>)", "Alan Turing 1912-1954")
'Alan Turing (1912-1954)'
\g<0> is a backreference to the entire match (\0 doesn't work; it would be interpreted as \x00).
\ g <0>是对整个匹配的反向引用(\ 0不起作用;它将被解释为\ x00)。
Solution 2:
>>> regex = re.compile(r"\d{4}-\d{4}")
>>> regex.sub(lambda m: '({0})'.format(m.group(0)), "Alan Turing 1912-1954")
'Alan Turing (1912-1954)'
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