Python根据第一项从2d数组中删除元素

If I were to have a 2d array in python, say

如果我在python中有一个2d数组,请说

lst = [['a','1', '2'], ['b', 1, 2], ['c', 1, 2], ['b', 3, 4]]

I'd like a way to remove any items from lst where the first item is 'b', so that you return with:

我想要一种方法从第一项是'b'的lst中删除任何项目,以便您返回:

[['a','1', '2'], ['c', 1, 2]]

Any help would be greatly appreciated, preferred if only built in libraries are used. Thanks

如果只使用内置的库,则会非常感谢任何帮助。谢谢

2 个解决方案

Use a list comprehension

使用列表理解

lst = [['a','1', '2'], ['b', 1, 2], ['c', 1, 2], ['b', 3, 4]]
lst = [x for x in lst if x[0] != 'b']
print(lst)

prints

[['a', '1', '2'], ['c', 1, 2]]