在Python / IPython解释器中为单个下划线_赋值

I created this function in Python 2.7 with ipython:

我使用ipython在Python 2.7中创建了这个函数：

def _(v):
    return v

later if I call _(somevalue), I get _ = somevalue.

后来如果我调用_（somevalue），我得到_ = somevalue。

in[3]: _(3)
out[3]: 3
in[4]: print _
out[4]: 3

The function has disappeared! If I call _(4) I get:

功能消失了！如果我打电话给_（4）我得到：

TypeError: 'int' object is not callable`

Why? What's wrong with this function?

为什么？这个功能有什么问题？

3 个解决方案

#1

101

The Python interpreter assigns the last expression value to _.

Python解释器将最后一个表达式值赋给_。

This behaviour is limited to the REPL interpreter only, and is intended to assist in interactive coding sessions:

此行为仅限于REPL解释器，旨在帮助进行交互式编码会话：

>>> import math
>>> math.pow(3.0, 5)
243.0
>>> result = _
>>> result
243.0

The standard Python interpreter goes to some length to not trample on user-defined values though; if you yourself assign something else to _ then the interpreter will not overwrite that (technically speaking, the _ variable is a __builtin__ attribute, your own assignments are 'regular' globals). You are not using the standard Python interpreter though; you are using IPython, and that interpreter is not that careful.

标准的Python解释器有一定篇幅，但不会践踏用户定义的值;如果你自己为_分配其他东西，那么解释器就不会覆盖它（从技术上讲，_变量是__builtin__属性，你自己的赋值是'常规'全局变量）。你没有使用标准的Python解释器;你正在使用IPython，那个解释器并不那么谨慎。

IPython documents this behaviour explicitly:

IPython明确记录了这种行为：

The following GLOBAL variables always exist (so don’t overwrite them!):

以下GLOBAL变量始终存在（因此不要覆盖它们！）：

[_] (a single underscore) : stores previous output, like Python’s default interpreter.

[_]（单个下划线）：存储以前的输出，如Python的默认解释器。

[...]

[...]

Outside of the Python interpreter, _ is by convention used as the name of the translatable text function (see the gettext module; external tools look for that function to extract translatable strings).

在Python解释器之外，_按惯例用作可翻译文本函数的名称（请参阅gettext模块;外部工具查找该函数以提取可翻译的字符串）。

In loops, using _ as an assignment target tells readers of your code that you are going to ignore that value; e.g. [random.random() for _ in range(5)] to generate a list of 5 random float values.

在循环中，使用_作为赋值目标告诉读者您的代码将忽略该值;例如[random_random（）for _ in range（5）]生成5个随机浮点值的列表。

3 个解决方案

#1

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