如何在qt上访问父窗口小部件？

I have an inherited QTreeWidget (called PackList) class and its parent is a KXmlGuiWindow. How can I access to the parent's slots?

我有一个继承的QTreeWidget(称为PackList)类,其父级是KXmlGuiWindow。如何访问父母的插槽?

I've tried getParent()->mySlot() from the QTreeWidget class but I've got

我已经尝试过来自QTreeWidget类的getParent() - > mySlot()但我已经有了

error: no matching function for call to 'PackList::mySlot()'

Does anybody know the correct way? Thanks

有人知道正确的方法吗?谢谢

2 个解决方案

#1

If you know the parent's class, you will have to cast parentWidget() to that class and then call your slot. Keep in mind whether or not it's a slot makes no difference in this case. You are just calling a method.

如果您知道父类,则必须将parentWidget()强制转换为该类,然后调用您的插槽。请记住,在这种情况下,它是否是一个插槽没有区别。你只是在调用一种方法。

((KXmlGuiWindow*)parentWidget())->mySlot();

You can make the call without casting by wiring up your signal to the slot.

您可以通过将信号连接到插槽来进行无需转换的呼叫。

connect( this, SIGNAL(mySignal()), parentWidget(), SLOT(mySlot()) );

Lastly, you can use QMetaObject::invokeMethod to call it if you don't want to cast it. That's probably overkill.

最后,如果您不想强制转换它,可以使用QMetaObject :: invokeMethod来调用它。这可能是矫枉过正的。

2 个解决方案

#1

更多相关文章

随机推荐