将muilti维Json数组解析为Python
I'm in over my head, trying to parse JSON for my first time and dealing with a multi dimensional array.
我在我脑海中,试图第一次解析JSON并处理多维数组。
{
"secret": "[Hidden]",
"minutes": 20,
"link": "http:\/\/www.1.com",
"bookmark_collection": {
"free_link": {
"name": "#free_link#",
"bookmarks": [
{
"name": "1",
"link": "http:\/\/www.1.com"
},
{
"name": "2",
"link": "http:\/\/2.dk"
},
{
"name": "3",
"link": "http:\/\/www.3.in"
}
]
},
"boarding_pass": {
"name": "Boarding Pass",
"bookmarks": [
{
"name": "1",
"link": "http:\/\/www.1.com\/"
},
{
"name": "2",
"link": "http:\/\/www.2.com\/"
},
{
"name": "3",
"link": "http:\/\/www.3.hk"
}
]
},
"sublinks": {
"name": "sublinks",
"link": [
"http:\/\/www.1.com",
"http:\/\/www.2.com",
"http:\/\/www.3.com"
]
}
}
}
This is divided into 3 parts, the static data on my first dimension (secret, minutes, link) Which i need to get as seperate strings.
这分为3个部分,我的第一个维度上的静态数据(秘密,分钟,链接)我需要作为单独的字符串获取。
Then I need a dictionary per "bookmark collection" which does not have fixed names, so I need the name of them and the links/names of each bookmark.
然后我需要一个没有固定名称的“书签集”字典,所以我需要它们的名称和每个书签的链接/名称。
Then there is the seperate sublinks which is always the same, where I need all the links in a seperate dictionary.
然后是单独的子链接,它总是相同的,我需要单独的字典中的所有链接。
I'm reading about parsing JSON but most of the stuff I find is a simple array put into 1 dictionary. Does anyone have any good techniques to do this ?
我正在阅读有关解析JSON的内容,但我发现的大多数内容都是放入1个字典中的简单数组。有没有人有任何好的技巧来做到这一点?
2 个解决方案
#1
11
After you parse the JSON, you will end up with a Python dict. So, suppose the above JSON is in a string named input_data:
在解析JSON之后,最终会得到一个Python dict。因此,假设上面的JSON位于名为input_data的字符串中:
import json
# This converts from JSON to a python dict
parsed_input = json.loads(input_data)
# Now, all of your static variables are referenceable as keys:
secret = parsed_input['secret']
minutes = parsed_input['minutes']
link = parsed_input['link']
# Plus, you can get your bookmark collection as:
bookmark_collection = parsed_input['bookmark_collection']
# Print a list of names of the bookmark collections...
print bookmark_collection.keys() # Note this contains sublinks, so remove it if needed
# Get the name of the Boarding Pass bookmark:
print bookmark_collection['boarding_pass']['name']
# Print out a list of all bookmark links as:
# Boarding Pass
# * 1: http://www.1.com/
# * 2: http://www.2.com/
# ...
for bookmark_definition in bookmark_collection.values():
# Skip sublinks...
if bookmark_definition['name'] == 'sublinks':
continue
print bookmark_definition['name']
for bookmark in bookmark_definition['bookmarks']:
print " * %(name)s: %(link)s" % bookmark
# Get the sublink definition:
sublinks = parsed_input['bookmark_collection']['sublinks']
# .. and print them
print sublinks['name']
for link in sublinks['link']:
print ' *', link
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